tolong dong besok dikumpulin
Jawab:
fungsi invers
4. f(x) = x² + 2x + 3
x² + 2x = f(x) - 3
(x + 1)² = f(x) - 3 + 1
(x + 1)² = f(x) - 2
[tex]\sf (x +1) = \pm\sqrt{f(x) - 2}[/tex]
[tex]\sf x = -1\pm\sqrt{f(x) - 2}[/tex]
[tex]\sf f^{-1}(x) = -1 \pm \sqrt{x-2}[/tex]
5. f(x) = x³
x³ = f(x)
x = ∛ f(x)
[tex]\sf f^{-1}(x) = \sqrt[3]{x}[/tex]
